Physics Formulae Electricity Electrical Resonance

Subset – Definition and Properties

Learn the electrical resonance formula, used to find the frequency where inductive and capacitive reactance are equal. E...

Definition of Electrical Resonance

Electrical resonance occurs in an AC circuit when the inductive reactance equals the capacitive reactance (\(X_L = X_C\)) at a specific frequency, called the resonant frequency (\(f_0\)). At this frequency, the reactive components cancel each other out, leaving only the circuit's resistance to oppose the flow of current. This results in minimum impedance, maximum current, a zero-degree phase shift between voltage and current, and a unity power factor (maximum efficiency).

Physically, resonance represents the natural oscillation frequency of an LC circuit where energy alternates between the electric field of the capacitor and the magnetic field of the inductor. The phenomenon is analogous to mechanical resonance, where a system oscillates with maximum amplitude when driven at its natural frequency. The resonant frequency depends only on the values of the inductance (L) and capacitance (C).

Physical Properties

Electrical resonance is a condition in an AC circuit where the reactive effects of inductors and capacitors cancel each other out, leading to a purely resistive impedance at a specific frequency.

PropertyDetails
NatureResonance is a phenomenon or condition. The key associated quantity, resonant frequency, is a scalar.
SI UnitsThe resonant frequency (f₀) is measured in Hertz (Hz). Reactance and impedance are measured in Ohms (Ω).
Key RelationshipsAt resonance, inductive reactance (X_L) equals capacitive reactance (X_C). The total impedance (Z) of a series circuit is at its minimum, equal to the resistance (R).
Energy ExchangeAt resonance, energy is optimally transferred between the inductor's magnetic field and the capacitor's electric field. The net reactive power is zero, and all power from the source is dissipated by the resistor.
Dimensional FormulaThe dimensional formula for resonant frequency is [M⁰ L⁰ T⁻¹].
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Diagram & Visualization

f X, Z f₀ R X_L X_C Z
Graph of reactances (X_L, X_C) and impedance (Z) versus frequency (f), showing resonance where X_L equals X_C.
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Key Formulas

\[ f_0 = \frac{1}{2\pi\sqrt{LC}} \]
Resonant Frequency (in Hertz)
\[ \omega_0 = \frac{1}{\sqrt{LC}} \]
Resonant Angular Frequency
\[ Q = \frac{\omega_0 L}{R} = \frac{1}{\omega_0 RC} = \frac{1}{R}\sqrt{\frac{L}{C}} \]
Quality Factor (Q)
\[ BW = \frac{f_0}{Q} = \frac{R}{2\pi L} \]
Bandwidth
\[ Z_{\text{min}} = R, \quad I_{\text{max}} = \frac{V}{R} \]
Conditions at Series Resonance
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Variables and Symbols

SymbolQuantitySI UnitDescription
\(f_0\)Resonant FrequencyHertz (Hz)The frequency at which reactances cancel (\(X_L = X_C\)).
\(\omega_0\)Resonant Angular Frequencyradians/second (rad/s)The resonant frequency expressed in angular terms (\(\omega_0 = 2\pi f_0\)).
LInductanceHenry (H)A measure of a circuit element's ability to store energy in a magnetic field.
CCapacitanceFarad (F)A measure of a circuit element's ability to store energy in an electric field.
RResistanceOhm (Ω)The opposition to current flow that dissipates energy as heat.
ZImpedanceOhm (Ω)The total opposition to current flow in an AC circuit (resistive and reactive).
\(X_L\)Inductive ReactanceOhm (Ω)The opposition to current flow from an inductor, increasing with frequency.
\(X_C\)Capacitive ReactanceOhm (Ω)The opposition to current flow from a capacitor, decreasing with frequency.
QQuality FactorDimensionlessA measure of the sharpness of the resonance peak and the selectivity of the circuit.
BWBandwidthHertz (Hz)The range of frequencies for which the circuit response is significant (above half-power).
\(\phi\)Phase Angledegrees (°) or radians (rad)The phase difference between voltage and current. It is zero at resonance.
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Derivation of Resonant Frequency

The resonant frequency is derived from the fundamental condition of resonance: the inductive reactance (\(X_L\)) must equal the capacitive reactance (\(X_C\)).

\[ X_L = X_C \]
Step 1: Set reactances equal

Substitute the formulas for inductive and capacitive reactance, where \(\omega\) is the angular frequency (\(\omega = 2\pi f\)).

\[ \omega L = \frac{1}{\omega C} \]
Step 2: Substitute reactance formulas

Rearrange the equation to solve for \(\omega^2\). This frequency is specifically the resonant angular frequency, so we label it \(\omega_0\).

\[ \omega_0^2 LC = 1 \]
Step 3: Rearrange the terms

Finally, take the square root of both sides to find the expression for the resonant angular frequency, \(\omega_0\).

\[ \omega_0 = \frac{1}{\sqrt{LC}} \]
Step 4: Solve for resonant angular frequency

To find the resonant frequency in Hertz (\(f_0\)), we use the relationship \(\omega_0 = 2\pi f_0\).

\[ f_0 = \frac{\omega_0}{2\pi} = \frac{1}{2\pi\sqrt{LC}} \]
Step 5: Convert to frequency in Hertz
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Types & Special Cases

Electrical resonance is classified primarily based on the circuit configuration, which determines its behavior and application.

Type / CaseDescriptionWhen to Use
Series ResonanceIn a series RLC circuit, impedance is at a minimum at resonance, causing maximum current to flow. It acts as a voltage amplifier for the capacitor and inductor voltages.Used in tuning circuits for radio receivers and band-pass filters to select a specific frequency.
Parallel ResonanceIn a parallel RLC circuit, impedance is at a maximum at resonance, causing minimum current to be drawn from the source. It is sometimes called anti-resonance.Used in band-stop or notch filters to block a specific frequency, and in oscillator circuits.
High-Q ResonanceA circuit with a high Quality Factor (Q) has a very sharp and narrow resonance peak. This means it is highly selective to a small range of frequencies.Used when precise frequency selection is critical, such as in high-fidelity radio tuners and signal generators.
Low-Q ResonanceA circuit with a low Quality Factor (Q) has a broad and flat resonance peak. This means it responds to a wider range of frequencies around the resonant frequency.Used in applications where a wider band of frequencies needs to be passed, such as in audio equalizers or general-purpose filters.
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Worked Example

A series RLC circuit has a resistor R = 10 Ω, an inductor L = 5 mH, and a capacitor C = 20 μF. Calculate its resonant frequency (f₀), quality factor (Q), and bandwidth (BW).
  1. Calculate the resonant frequency using the formula \(f_0 = \frac{1}{2\pi\sqrt{LC}}\).<br>\(f_0 = \frac{1}{2\pi\sqrt{(5 \times 10^{-3} \text{ H}) \times (20 \times 10^{-6} \text{ F})}} = \frac{1}{2\pi\sqrt{10^{-7}}} \approx 503.3 \text{ Hz}\)
  2. Calculate the quality factor using the formula \(Q = \frac{1}{R}\sqrt{\frac{L}{C}}\).<br>\(Q = \frac{1}{10 \text{ } \Omega}\sqrt{\frac{5 \times 10^{-3} \text{ H}}{20 \times 10^{-6} \text{ F}}} = \frac{1}{10}\sqrt{250} \approx 1.58\)
  3. Calculate the bandwidth using the formula \(BW = \frac{f_0}{Q}\).<br>\(BW = \frac{503.3 \text{ Hz}}{1.58} \approx 318.5 \text{ Hz}\)
The circuit has a resonant frequency of approximately 503.3 Hz, a quality factor of 1.58, and a bandwidth of 318.5 Hz.
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Try It

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Applications of Electrical Resonance

Communication Systems: Resonant circuits are fundamental to radio and television tuning. By adjusting the capacitance or inductance, a receiver can be tuned to the resonant frequency of a specific broadcast station, maximizing its signal strength while rejecting others.

Filter Circuits: In audio and signal processing, resonant circuits are used to create filters that pass or block specific frequency ranges. Examples include band-pass filters, which allow a narrow band of frequencies around resonance to pass, and notch filters, which block them.

Induction Heating: Industrial processes like metal melting and heat treatment use resonant LC circuits to drive a work coil. Operating at the resonant frequency ensures maximum power transfer from the supply to the coil, enabling efficient and rapid heating.

Power Systems: Resonant filters are used in power distribution systems to suppress unwanted harmonic frequencies generated by non-linear loads. By tuning a filter to a specific harmonic (e.g., the 5th harmonic at 300 Hz in a 60 Hz system), it can effectively short-circuit and remove that unwanted frequency, improving power quality.

Wireless Power Transfer: Resonant inductive coupling allows for efficient wireless charging of devices like smartphones and electric vehicles. Coils in both the charger and the device are tuned to the same resonant frequency, maximizing the energy transfer over an air gap.

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Real-World Examples

An engineer is designing a simple AM radio tuner using a series RLC circuit. The goal is to tune into a station at 1200 kHz. The circuit uses a fixed inductor of L = 200 µH and a variable capacitor. What capacitance is required to achieve resonance at this frequency? If the total circuit resistance is 15 Ω, what is the bandwidth of the receiver?
  1. Rearrange the resonant frequency formula to solve for C: \(C = \frac{1}{(2\pi f_0)^2 L}\).
  2. Substitute the known values: \(C = \frac{1}{(2\pi \times 1200 \times 10^3)^2 \times (200 \times 10^{-6})} \approx 88.0 \text{ pF}\).
  3. First, calculate the Quality Factor Q: \(Q = \frac{2\pi f_0 L}{R} = \frac{2\pi (1200 \times 10^3)(200 \times 10^{-6})}{15} \approx 100.5\).
  4. Now, calculate the bandwidth: \(BW = \frac{f_0}{Q} = \frac{1200 \text{ kHz}}{100.5} \approx 11.94 \text{ kHz}\).
The variable capacitor must be set to approximately 88.0 pF to receive the 1200 kHz station. The receiver will have a bandwidth of about 11.94 kHz, allowing it to clearly select the station.
A factory uses a large motor that creates significant 5th harmonic distortion (300 Hz on a 60 Hz system). To improve power quality, a series resonant filter is designed to be placed in parallel with the motor. If a 100 µF capacitor is used, what inductance is needed to create resonance at 300 Hz? If the filter's resistance is 0.5 Ω, what is its impedance to the 5th harmonic versus the fundamental 60 Hz frequency?
  1. Calculate the required inductance for resonance at 300 Hz: \(L = \frac{1}{(2\pi f_0)^2 C} = \frac{1}{(2\pi \times 300)^2 \times (100 \times 10^{-6})} \approx 2.81 \text{ mH}\).
  2. At the resonant frequency (300 Hz), the impedance of the filter is just its resistance: \(Z(300 \text{ Hz}) = R = 0.5 \text{ }\Omega\). This low impedance effectively shunts the harmonic current.
  3. Calculate the reactances at the fundamental frequency (60 Hz):<br>\(X_L = 2\pi(60)(2.81 \times 10^{-3}) \approx 1.06 \text{ }\Omega\)<br>\(X_C = \frac{1}{2\pi(60)(100 \times 10^{-6})} \approx 26.53 \text{ }\Omega\)
  4. Calculate the total impedance at 60 Hz: \(Z(60 \text{ Hz}) = \sqrt{R^2 + (X_L - X_C)^2} = \sqrt{0.5^2 + (1.06 - 26.53)^2} \approx 25.48 \text{ }\Omega\).
An inductance of 2.81 mH is needed. The filter presents a very low impedance of 0.5 Ω to the unwanted 300 Hz harmonic, effectively removing it, while presenting a high impedance of 25.48 Ω to the desired 60 Hz fundamental frequency, leaving it unaffected.
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Real-World Scenarios

Tuning a Radio
Adjusting a radio's capacitor changes its circuit's resonant frequency. When it matches a station's signal, resonance amplifies that specific frequency.
Wireless Charging
A charging pad and a device contain coils tuned to the same resonant frequency. This resonant coupling allows for efficient wireless energy transfer.
Metal Detector
A metal detector's coil has a resonant frequency. When a metal object enters its magnetic field, it disrupts the resonance, which triggers an alarm.

Tuning a Radio
When you turn the dial of an analog radio, you are typically adjusting a variable capacitor. This changes the resonant frequency of an internal LC circuit. When that frequency matches the carrier frequency of a radio station, the circuit resonates, causing a large current to flow for that specific frequency, which amplifies the station's signal so you can hear it clearly.

Wireless Charging Pad
An inductive charging pad for a smartphone contains a coil that generates an oscillating magnetic field. A corresponding coil in the phone is designed to have the same resonant frequency. This resonant coupling allows energy to be transferred efficiently across the small air gap, charging the battery without any physical connection.

Metal Detectors
A metal detector works by using a resonant circuit to generate an alternating magnetic field in a search coil. When a metal object passes nearby, it induces eddy currents in the metal. These currents create their own magnetic field, which disrupts the resonant frequency of the search coil, triggering an alarm.

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Limitations and Assumptions

⚠️ Ideal Component Assumption: The standard resonance formulas assume ideal inductors, capacitors, and resistors. Real-world components have parasitic properties (e.g., equivalent series resistance (ESR) in capacitors, winding resistance in inductors) that can shift the actual resonant frequency and lower the Quality Factor.
⚠️ Component Tolerances: The calculated resonant frequency is only as precise as the component values used. Standard electronic components have manufacturing tolerances (e.g., ±5% or ±10%), which means the actual resonant frequency of a physical circuit may differ from the designed value.
💡 High-Frequency Effects: At very high frequencies, the physical size of components and traces can introduce stray capacitance and inductance, altering the circuit's resonant behavior. The lumped-element model (treating L and C as discrete components) may break down, requiring a distributed-element analysis.

Common Mistakes

⚠️ Mixing Angular Frequency (ω) and Frequency (f): A frequent error is forgetting the \(2\pi\) factor. The formula \(\omega_0 = 1/\sqrt{LC}\) gives the answer in radians per second, while \(f_0 = 1/(2\pi\sqrt{LC})\) gives the answer in Hertz. Using the wrong formula will result in an answer that is off by a factor of \(2\pi \approx 6.28\).
⚠️ Confusing Series and Parallel Resonance: While the resonant frequency formula is the same for both, their circuit characteristics are opposite. In series resonance, impedance is at a MINIMUM (Z=R). In parallel resonance, impedance is at a MAXIMUM. Applying the minimum impedance characteristic to a parallel circuit is a common conceptual error.
⚠️ Ignoring Resistance for Q Factor: The resonant frequency \(f_0\) is independent of resistance R. However, the sharpness of the resonance (the Q factor) and the bandwidth are critically dependent on R. A common mistake is to analyze the selectivity of a circuit without considering the damping effect of resistance.
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Units and Dimensions

QuantitySymbolSI UnitDimensional Formula
Frequency\(f\)Hertz (Hz)[T⁻¹]
Angular Frequency\(\omega\)radians/second (rad/s)[T⁻¹]
InductanceLHenry (H)[M L² T⁻² I⁻²]
CapacitanceCFarad (F)[M⁻¹ L⁻² T⁴ I²]
ResistanceROhm (Ω)[M L² T⁻³ I⁻²]
Impedance / ReactanceZ, XOhm (Ω)[M L² T⁻³ I⁻²]
Quality FactorQDimensionless1

Dimensional Analysis of Resonant Frequency: Let's check the dimensions for \(\omega_0 = 1/\sqrt{LC}\).
Dimension of \(LC\) is \([M L^2 T^{-2} I^{-2}] \times [M^{-1} L^{-2} T^4 I^2] = [T^2]\).
Therefore, the dimension of \(\sqrt{LC}\) is \([T]\).
The dimension of \(1/\sqrt{LC}\) is \([T^{-1}]\), which is the correct dimension for angular frequency.

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Study Strategy

1 🧠 Grasp the Fundamentals
  • Read the DEFINITION section to understand that resonance is when inductive reactance (XL) equals capacitive reactance (XC).
  • Visualize the core effect: At resonance, reactive components cancel, minimizing impedance and maximizing current in a series RLC circuit.
  • Note the key outcome from the DEFINITION: The phase angle between voltage and current becomes zero, meaning they are perfectly in sync.
  • Focus on the concept of resonant frequency (f₀) as the specific frequency where this phenomenon occurs.
2 📝 Commit the Formula to Memory
  • Write down the foundational relationship that leads to the formula: XL = XC, which is 2πfL = 1/(2πfC).
  • Memorize the primary formula for resonant frequency in Hertz: f₀ = 1/(2π√LC).
  • Also learn the formula for angular resonant frequency, which is simpler: ω₀ = 1/√LC.
  • Create a flashcard with both formulas and the definitions of L (inductance) and C (capacitance).
3 ✍️ Practice with Problems
  • Solve problems where you are given L and C values and must calculate the resonant frequency, f₀.
  • Heed the warning in the COMMON_MISTAKES section: always check if you need frequency (f) or angular frequency (ω) to avoid a 2π error.
  • Practice calculating impedance (Z) at resonance. Remember, at this specific frequency, impedance is at its minimum and Z = R.
  • Review the COMMON_MISTAKES section to understand the key differences between series and parallel resonance, as their behavior is distinct.
4 🌍 Connect to Real-World Physics
  • Study the APPLICATIONS section to see how resonance is fundamental to tuning radios and TVs, selecting one station's frequency.
  • Consider how filter circuits, as mentioned in the APPLICATIONS, use resonance to pass or block specific frequencies in audio and signal processing.
  • Think of a car radio: turning the dial changes C or L to match the resonant frequency of a new station, maximizing its signal.
  • Recognize resonance in other technologies like wireless charging pads and metal detectors, which operate on similar principles.
Master electrical resonance by understanding the core concept of matched reactances, memorizing the formula, practicing calculations, and connecting it to everyday tuning technology.

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