Physics Formulae Mechanics Plastic Collision

Subset – Definition and Properties

Learn to use the Plastic Collision formula to find the final velocity when two objects stick together after impact. Esse...
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What is a Plastic Collision?

A plastic collision, also known as a perfectly inelastic collision, occurs when two objects collide and stick together after impact, moving as a single combined object with the same final velocity. This represents the maximum possible kinetic energy loss while still conserving momentum. Despite the name "plastic," this term applies to any collision where objects remain joined after impact, whether through deformation, adhesion, or mechanical coupling.

\[ v_{1f} = v_{2f} = v_f \]
Defining Characteristic: Common Final Velocity

Conservation Laws:

  • Momentum is conserved: \( m_1v_1 + m_2v_2 = (m_1 + m_2)v_f \)
  • Kinetic energy is NOT conserved (maximum loss possible)
  • Energy is converted into other forms, such as heat, sound, and permanent deformation.

Physical Properties

A plastic collision, also known as a perfectly inelastic collision, is defined by the conservation of linear momentum and the maximum possible loss of kinetic energy. The key characteristic is that the colliding bodies stick together and move with a single, common velocity after impact.

PropertyDetails
Conservation LawsLinear momentum is conserved. Kinetic energy is not conserved; it is maximally converted into other forms (heat, sound, deformation).
Key FeatureThe colliding objects coalesce or stick together, moving as a single mass with a common final velocity after the collision.
Relevant QuantitiesMass (kg), Velocity (m/s), and Momentum (kg⋅m/s) are the primary quantities. The change in Kinetic Energy (Joules) is also a critical outcome.
Vector NatureMomentum and velocity are vector quantities. In collisions occurring in more than one dimension, momentum must be conserved independently along each axis.
Dimensional FormulaThe dimensional formula for the conserved quantity, momentum, is [M][L][T]⁻¹. The dimensional formula for kinetic energy is [M][L]²[T]⁻².
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Diagram & Visualization

Before m₁ v₁ m₂ v₂=0 After (m₁ + m₂) v_f
A plastic (perfectly inelastic) collision where two objects stick together and move as one after impact.
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Key Formulas

\[ v_f = \frac{m_1v_1 + m_2v_2}{m_1 + m_2} \]
Final Common Velocity
\[ \Delta KE_{max} = \frac{1}{2} \frac{m_1 m_2}{m_1 + m_2}(v_1 - v_2)^2 \]
Maximum Kinetic Energy Loss
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Variables and Symbols

SymbolQuantitySI UnitDescription
\( v_f \)Final Velocitym/sThe common velocity of both objects after they stick together.
\( m_1, m_2 \)MasskgThe masses of object 1 and object 2, respectively.
\( v_1, v_2 \)Initial Velocitym/sThe initial velocities of object 1 and object 2 before the collision.
\( p_i, p_f \)Momentumkg⋅m/sThe initial and final momentum of the system.
\( KE_i, KE_f \)Kinetic EnergyJThe initial and final kinetic energy of the system.
\( \Delta KE \)Change in Kinetic EnergyJThe amount of kinetic energy lost during the collision, converted to other forms.
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Derivation from First Principles

The formula for the final velocity in a plastic collision is derived directly from the principle of conservation of linear momentum, which states that the total momentum of an isolated system remains constant.

Step 1: Define the total initial momentum of the system.

The total momentum before the collision is the vector sum of the individual momenta of the two objects.

\[ p_i = m_1v_1 + m_2v_2 \]
Total Initial Momentum

Step 2: Define the total final momentum of the system.

After the collision, the two objects stick together, forming a single combined mass \( (m_1 + m_2) \) that moves with a common final velocity \( v_f \).

\[ p_f = (m_1 + m_2)v_f \]
Total Final Momentum

Step 3: Apply the conservation of momentum.

Equate the total initial momentum to the total final momentum.

\[ p_i = p_f \implies m_1v_1 + m_2v_2 = (m_1 + m_2)v_f \]
Conservation of Momentum Equation

Step 4: Solve for the final velocity \( v_f \).

Isolate \( v_f \) by dividing both sides by the total mass \( (m_1 + m_2) \).

\[ v_f = \frac{m_1v_1 + m_2v_2}{m_1 + m_2} \]
Derived Final Velocity
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Types & Special Cases

Plastic collisions can be classified based on the geometry of the impact and the initial state of motion of the colliding objects. Each case is solved by applying the principle of conservation of momentum.

Type / CaseDescriptionWhen to Use
One-Dimensional (Head-On)The initial velocities of both objects lie along the same straight line. The combined mass continues to move along this line.Used for problems where motion is constrained to a single axis, such as two carts on a track colliding and sticking together.
Two-Dimensional (Oblique)The initial velocities of the objects are not collinear. The combined mass moves off at an angle to the initial paths.Applicable for analyzing glancing collisions where objects fuse, requiring momentum to be conserved in two separate perpendicular components (e.g., x and y).
Stationary TargetA common scenario where one of the objects is at rest (initial velocity is zero) before being struck by the other.Simplifies the initial momentum calculation. A classic example is the ballistic pendulum, where a projectile embeds itself in a stationary block.
Explosions (Reverse Collision)While not a collision, the mathematics are identical but reversed in time. A single object breaks apart into multiple pieces.Used to analyze situations where internal forces push objects apart from an initial state of rest, like the recoil of a cannon when a shell is fired.
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Worked Example (Numerical)

Given m₁ = 2 kg, v₁ = 5 m/s, m₂ = 3 kg, and v₂ = -2 m/s. Find the final velocity \(v_f\) and the kinetic energy lost \(ΔKE\) in a perfectly inelastic collision.
  1. <b>Step 1: Calculate the final velocity using the plastic collision formula.</b><br>\[ v_f = \frac{m_1v_1 + m_2v_2}{m_1 + m_2} = \frac{(2)(5) + (3)(-2)}{2 + 3} = \frac{10 - 6}{5} = \frac{4}{5} = 0.8 \text{ m/s} \]
  2. <b>Step 2: Calculate the initial kinetic energy of the system.</b><br>\[ KE_i = \frac{1}{2}m_1v_1^2 + \frac{1}{2}m_2v_2^2 = \frac{1}{2}(2)(5)^2 + \frac{1}{2}(3)(-2)^2 = 25 + 6 = 31 \text{ J} \]
  3. <b>Step 3: Calculate the final kinetic energy of the system.</b><br>\[ KE_f = \frac{1}{2}(m_1 + m_2)v_f^2 = \frac{1}{2}(2 + 3)(0.8)^2 = \frac{1}{2}(5)(0.64) = 1.6 \text{ J} \]
  4. <b>Step 4: Calculate the kinetic energy lost.</b><br>\[ \Delta KE = KE_i - KE_f = 31 - 1.6 = 29.4 \text{ J} \]
The final common velocity is 0.8 m/s, and the kinetic energy lost is 29.4 J.
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Try It

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Applications

Automotive Safety

Used in crash test analysis, designing vehicle crumple zones, collision reconstruction, and developing safety systems.

Ballistics and Forensics

Applied to studies of bullet penetration, body armor testing, crime scene reconstruction, and ammunition design.

Materials Engineering

Essential for impact testing, material deformation studies, designing energy-absorbing composites, and failure analysis.

Sports Safety

Used in helmet design, development of protective equipment, injury prevention research, and setting rules for contact sports.

Industrial Design

Principles are used in the design of shock absorbers, protective packaging, machinery safety guards, and vibration dampening systems.

Aerospace Engineering

Important for designing spacecraft shielding against micrometeoroids, creating soft landing systems, and analyzing debris impacts.

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Real-World Numerical Examples

A 1500 kg car traveling east at 20 m/s collides with a 2000 kg truck traveling west at 15 m/s. The vehicles become entangled and move together after the crash. Find their common velocity and calculate the kinetic energy lost. (Assume east is the positive direction).
  1. <b>Step 1: Apply momentum conservation.</b> Initial momentum: \( p_i = m_1v_1 + m_2v_2 = (1500)(20) + (2000)(-15) = 30,000 - 30,000 = 0 \text{ kg⋅m/s} \). Final momentum: \( p_f = (m_1 + m_2)v_f = 0 \). Therefore, \( v_f = \frac{0}{1500 + 2000} = 0 \text{ m/s} \).
  2. <b>Step 2: Calculate initial kinetic energy.</b> \[ KE_i = \frac{1}{2}m_1v_1^2 + \frac{1}{2}m_2v_2^2 = \frac{1}{2}(1500)(20)^2 + \frac{1}{2}(2000)(15)^2 = 300,000 + 225,000 = 525,000 \text{ J} \]
  3. <b>Step 3: Calculate final kinetic energy and energy loss.</b> Final KE: \( KE_f = \frac{1}{2}(m_1 + m_2)v_f^2 = \frac{1}{2}(3500)(0)^2 = 0 \text{ J} \). Energy lost: \( \Delta KE = KE_i - KE_f = 525,000 - 0 = 525,000 \text{ J} \). The energy loss is 100%.
Final velocity = 0 m/s; Energy lost = 525 kJ (100%). This head-on collision with equal and opposite momenta demonstrates the maximum energy dissipation possible.
A 0.01 kg bullet traveling at 400 m/s embeds in a 2.0 kg wooden block initially at rest. Find the final velocity of the bullet-block system and calculate the energy lost to heat and deformation.
  1. <b>Step 1: Apply plastic collision formula.</b> \[ v_f = \frac{m_1v_1 + m_2v_2}{m_1 + m_2} = \frac{(0.01)(400) + (2.0)(0)}{0.01 + 2.0} = \frac{4.0}{2.01} \approx 1.99 \text{ m/s} \]
  2. <b>Step 2: Calculate energy before and after.</b> Initial KE: \( KE_i = \frac{1}{2}m_1v_1^2 = \frac{1}{2}(0.01)(400)^2 = 800 \text{ J} \). Final KE: \( KE_f = \frac{1}{2}(m_1 + m_2)v_f^2 = \frac{1}{2}(2.01)(1.99)^2 \approx 3.98 \text{ J} \).
  3. <b>Step 3: Analyze energy loss.</b> Energy lost: \( \Delta KE = KE_i - KE_f = 800 - 3.98 = 796.02 \text{ J} \). Percentage loss: \( \frac{796.02}{800} \times 100\% \approx 99.5\% \).
Final velocity ≈ 1.99 m/s; Energy lost ≈ 796 J (99.5%). This shows the massive energy dissipation when a small, fast object embeds in a larger target.
A 80 kg hockey player moving at 6 m/s north collides with a 75 kg opponent moving at 4 m/s east. They become tangled and move together. Find their common velocity (magnitude and direction).
  1. <b>Step 1: Find momentum components (east = +x, north = +y).</b> Player 1: \( p_{1x} = 0, p_{1y} = (80)(6) = 480 \text{ kg⋅m/s} \). Player 2: \( p_{2x} = (75)(4) = 300 \text{ kg⋅m/s}, p_{2y} = 0 \). Total momentum: \( p_x = 300, p_y = 480 \text{ kg⋅m/s} \).
  2. <b>Step 2: Find final velocity components.</b> Total mass \( m_{total} = 80 + 75 = 155 \text{ kg} \). \( v_{fx} = \frac{p_x}{m_{total}} = \frac{300}{155} \approx 1.94 \text{ m/s} \). \( v_{fy} = \frac{p_y}{m_{total}} = \frac{480}{155} \approx 3.10 \text{ m/s} \).
  3. <b>Step 3: Find magnitude and direction.</b> Magnitude: \( |v_f| = \sqrt{v_{fx}^2 + v_{fy}^2} = \sqrt{(1.94)^2 + (3.10)^2} \approx 3.66 \text{ m/s} \). Direction: \( \theta = \arctan(\frac{v_{fy}}{v_{fx}}) = \arctan(\frac{3.10}{1.94}) \approx 58.0° \) north of east.
Final velocity ≈ 3.66 m/s at 58.0° north of east. This demonstrates 2D plastic collision analysis.
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Scenarios in Everyday Life

Crumple Zones
A car's crumple zone deforms in a plastic collision, converting kinetic energy into work to protect passengers.
Modeling Clay
When two balls of clay collide, they stick together and deform in a perfectly inelastic collision, losing kinetic energy.
Catching a Football
A player catching a football is an inelastic collision where the ball and hands move as one, absorbing the ball's kinetic energy.

Automobile Crumple Zones

The front and rear sections of a car are designed to crumple during a severe collision. This intentional deformation creates a plastic collision, extending the impact time and converting the car's kinetic energy into the work of bending metal, which protects the passengers in the rigid safety cell.

Modeling Clay

When two balls of modeling clay are thrown at each other, they stick together and deform upon impact. This is a classic, tangible example of a perfectly inelastic collision where kinetic energy is lost to the work of deforming the clay and a small amount of heat.

Catching a Football

When a football player catches a pass, the ball and the player's hands (and body) move together as one unit immediately after the catch. This is an approximation of a plastic collision. The player's arms and body absorb the ball's kinetic energy to bring it to a stop relative to their body.

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Limitations and Assumptions

⚠️ The model assumes a perfectly inelastic collision where objects stick together completely. Real-world collisions might involve some rebound, fragmentation, or rotation, making the calculation an approximation.
⚠️ The principle of momentum conservation assumes an isolated system. External forces like friction (e.g., between tires and road) or air resistance are considered negligible during the brief duration of the impact, which is a valid assumption for most collision analyses.
💡 These formulas are valid within the framework of classical mechanics. They do not apply at relativistic speeds (a significant fraction of the speed of light) where mass is not constant and the principles of special relativity must be used.

Common Mistakes

⚠️ Incorrectly assuming kinetic energy is conserved. In a plastic collision, kinetic energy is maximally *lost*, not conserved. Only total momentum is conserved.
⚠️ Ignoring the vector nature of velocity. In 1D problems, forgetting to assign negative signs for motion in the opposite direction is a frequent error. In 2D problems, momentum must be conserved independently for each component (x and y).
⚠️ Calculating two different final velocities. The defining feature of a plastic collision is that the objects stick together and move with a single, common final velocity (v_f).
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Units and Dimensional Analysis

QuantitySymbolSI UnitDimensions
Mass\( m \)kilogram (kg)\( [M] \)
Velocity\( v \)meter per second (m/s)\( [L][T]^{-1} \)
Momentum\( p \)kilogram-meter per second (kg⋅m/s)\( [M][L][T]^{-1} \)
Kinetic Energy\( KE \)Joule (J)\( [M][L]^2[T]^{-2} \)

Dimensional Analysis of the Final Velocity Formula:

We can check the formula \( v_f = \frac{m_1v_1 + m_2v_2}{m_1 + m_2} \) for dimensional consistency. The dimensions of the numerator are those of momentum, \( [M][L][T]^{-1} \), and the dimensions of the denominator are those of mass, \( [M] \). Therefore:

\[ [v_f] = \frac{[M][L][T]^{-1}}{[M]} = [L][T]^{-1} \]

The resulting dimensions \( [L][T]^{-1} \) are those of velocity, confirming the formula is dimensionally correct.

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Study Strategy

1 🧠 Grasp the Fundamentals
  • Carefully read the DEFINITION section to understand why objects 'stick together' and move with a single final velocity.
  • Internalize the core principle: in a plastic collision, total momentum is conserved, but kinetic energy is maximally lost.
  • Contrast this concept with elastic collisions, where both momentum and kinetic energy are conserved.
  • Draw 'before' and 'after' diagrams for a simple collision to visualize the initial and final states of the system.
2 📝 Commit the Formula to Memory
  • Write the formula m₁v₁ᵢ + m₂v₂ᵢ = (m₁ + m₂)v_f multiple times until you can recall it perfectly.
  • Define each variable aloud: m₁ (mass 1), v₁ᵢ (initial velocity 1), m₂ (mass 2), v₂ᵢ (initial velocity 2), and v_f (final velocity).
  • Recognize that the formula is a direct application of the law of conservation of momentum for objects that combine.
  • Practice algebraically rearranging the formula to solve for the final velocity, v_f, as this is often the unknown variable.
3 ✍️ Practice with Problems
  • Work through a guided Worked Example step-by-step, focusing on how initial values are substituted into the formula.
  • Review the COMMON_MISTAKES section. Always account for the vector nature of velocity by assigning positive and negative signs for direction.
  • Solve a problem that requires calculating the kinetic energy lost to reinforce that KE is not conserved in these collisions.
  • Attempt a 2D problem, remembering to conserve momentum independently for the x and y components as noted in the COMMON_MISTAKES section.
4 🌍 Connect to Real-World Physics
  • Read the Automotive Safety application and explain how car crumple zones use plastic collision principles to protect passengers.
  • Explore the Ballistics and Forensics application. Think about how a ballistic pendulum uses a plastic collision to determine a bullet's speed.
  • Consider the Materials Engineering application to understand how impact tests analyze energy absorption during deformation.
  • Identify an everyday example of a plastic collision, like a raindrop hitting a car window, and describe the momentum transfer.
Master plastic collisions by understanding momentum conservation, practicing with vector velocities, and connecting the formula to real-world impacts.

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