Physics Formulae Thermal Physics Gay-Lussac's Law Of Pressure-Temperature

Subset – Definition and Properties

Master Gay-Lussac's Law to calculate how a gas's pressure changes with temperature in a fixed volume. A key concept for...
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Definition

Gay-Lussac's Law, formulated by Joseph Louis Gay-Lussac in 1802, states that for a fixed amount of gas at constant volume, the pressure is directly proportional to the absolute temperature. This law describes isochoric (constant volume) processes and shows that gas pressure increases linearly with temperature when volume is held fixed. The law can be expressed in two equivalent forms: the ratio form (p/T = constant) for comparing different states, and the linear coefficient form showing how pressure varies with Celsius temperature. This relationship is fundamental to understanding gas behavior in rigid containers and forms one of the cornerstone gas laws.

Joseph Louis Gay-Lussac (1778-1850) was a French chemist and physicist who formulated the pressure-temperature law. His original research in 1802 involved studying gas expansion and pressure changes with temperature by measuring gas pressure in rigid containers at different temperatures. He discovered a universal temperature coefficient γ ≈ 1/273 for all gases, and recognized that extrapolating the pressure to zero pointed to a temperature of -273°C, providing historical evidence for the absolute temperature scale.

Physical Properties

Gay-Lussac's Law describes the direct relationship between the pressure and absolute temperature of a gas, highlighting key physical properties under the specific constraints of constant volume and a fixed amount of gas.

PropertyDetails
Scalar/Vector NatureThe law relates scalar quantities: pressure (P) and absolute temperature (T). It does not involve any vector components.
SI UnitsPressure is measured in Pascals (Pa) and temperature must be expressed in Kelvin (K) for the direct proportionality to hold. Volume (held constant) is in cubic meters (m³).
Governing PrincipleThe pressure of a fixed mass of gas at constant volume is directly proportional to its absolute temperature. This means if the absolute temperature doubles, the pressure also doubles.
Underlying MechanismThis relationship stems from the kinetic theory of gases. Increasing the temperature increases the average kinetic energy of gas molecules, causing them to collide more frequently and forcefully with the container walls, thus increasing pressure.
Dimensional FormulaThe ratio P/T is constant. The dimensions of this constant are [M L⁻¹ T⁻² Θ⁻¹], where M is Mass, L is Length, T is Time, and Θ is Temperature.
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Diagram & Visualization

p₁ T₁ Heat p₂ T₂ p / T = constant (V fixed)
As temperature (T) increases in a fixed volume (V), gas pressure (p) increases proportionally.
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Key Formulas

\[ \frac{p}{T} = \text{constant} \]
Ratio Form
\[ \frac{p_1}{T_1} = \frac{p_2}{T_2} \]
State Comparison Form
\[ p = p_0\left(1 + \gamma t\right) = p_0 \left( 1 + \frac{1}{273.15} t \right) \]
Linear Coefficient Form (Celsius)
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Variables

SymbolQuantitySI UnitDescription
\(p, p_1, p_2\)PressurePascal (Pa)The force exerted by the gas per unit area. Subscripts denote different states.
\(T, T_1, T_2\)Absolute TemperatureKelvin (K)The absolute temperature of the gas. Must be in Kelvin for ratio calculations.
\(V\)Volumecubic meter (m³)The volume of the container, which must be held constant for the law to apply.
\(t\)Celsius Temperaturedegree Celsius (°C)Temperature on the Celsius scale, used in the linear coefficient form.
\(p_0\)Reference PressurePascal (Pa)The pressure of the gas at the reference temperature of 0°C (273.15 K).
\(\gamma\)Temperature Coefficient of PressureK⁻¹The fractional change in pressure per degree Celsius, approximately 1/273.15 K⁻¹ for ideal gases.
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Derivation

Gay-Lussac's Law can be derived from the kinetic theory of gases or observed experimentally. The law states a direct proportionality between pressure and absolute temperature for a fixed mass of gas at constant volume.

\[ p \propto T \quad \text{(at constant V, n)} \]
Direct Proportionality

This proportionality can be written as an equation with a constant of proportionality, \(k\).

\[ \frac{p}{T} = k \]
Ratio Form

This implies that for any two states (1 and 2) of the gas, the ratio of pressure to absolute temperature is the same.

\[ \frac{p_1}{T_1} = \frac{p_2}{T_2} \]
State Comparison

The linear form relating pressure to Celsius temperature can be derived by substituting the relationship between Kelvin (T) and Celsius (t), where \(T = t + 273.15\). Let \(p_0\) be the pressure at \(t=0\)°C (so \(T_0 = 273.15\) K).

\[ \frac{p}{T} = \frac{p_0}{T_0} \implies p = p_0 \frac{T}{T_0} \]
\[ p = p_0 \frac{(t + 273.15)}{273.15} = p_0 \left(1 + \frac{t}{273.15}\right) \]
\[ p = p_0(1 + \gamma t) \quad \text{where } \gamma = \frac{1}{273.15} \text{ K}^{-1} \]
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Types & Special Cases

Gay-Lussac's Law is a specific application within the broader framework of the ideal gas laws, each describing gas behavior under different constant conditions.

Type / CaseDescriptionWhen to Use
Isochoric ProcessThis is the direct application of Gay-Lussac's Law, describing a thermodynamic process that occurs at constant volume. The formula P₁/T₁ = P₂/T₂ is used to compare two states.For systems with a fixed amount of gas in a rigid, sealed container that is being heated or cooled, such as a pressure cooker or an aerosol can.
Ideal Gas Law SpecializationGay-Lussac's Law is a special case derived from the Ideal Gas Law (PV = nRT) by holding the volume (V) and the number of moles (n) constant.Useful for simplifying problems where volume and the amount of gas do not change, allowing for a direct calculation between initial and final pressure/temperature states.
Real Gas DeviationThe law is an accurate approximation for gases at low pressures and high temperatures. Real gases deviate from this ideal behavior at high pressures or low temperatures where intermolecular forces and molecular volume are significant.In high-precision or extreme condition scenarios (e.g., industrial chemical processes, cryogenics), where more complex models like the van der Waals equation are needed to account for non-ideal behavior.
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Worked Example

A gas in a rigid container has a pressure of 150 kPa at a temperature of 27°C. The gas is heated until its pressure reaches 200 kPa. What is the final temperature in degrees Celsius?
  1. Identify the initial and final states. Given: \(p_1 = 150\) kPa, \(t_1 = 27\)°C, \(p_2 = 200\) kPa.
  2. Convert the initial temperature to Kelvin: \(T_1 = 27 + 273.15 = 300.15\) K.
  3. State Gay-Lussac's Law for comparing two states: \( \frac{p_1}{T_1} = \frac{p_2}{T_2} \).
  4. Rearrange the formula to solve for the final temperature, \(T_2\): \( T_2 = T_1 \times \frac{p_2}{p_1} \).
  5. Substitute the known values into the equation: \( T_2 = 300.15 \text{ K} \times \frac{200 \text{ kPa}}{150 \text{ kPa}} = 300.15 \times \frac{4}{3} = 400.2 \text{ K} \).
  6. Convert the final temperature back to degrees Celsius: \( t_2 = 400.2 - 273.15 = 127.05 \)°C.
The final temperature is 400.2 K, or 127.05°C.
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Try It

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Applications

Gas Thermometry: Constant-volume gas thermometers use the linear relationship between pressure and temperature to provide a highly accurate temperature standard.

Pressure Vessels and Safety: The law is critical for designing and operating pressure vessels like steam boilers, autoclaves, and pressure cookers. It predicts the pressure increase upon heating, which informs the design of safety relief valves.

Automotive Systems: In a car's cooling system, the pressure inside the radiator increases as the engine heats up. The law helps engineers design radiator caps that can withstand this pressure. It also explains why tire pressure increases after driving.

HVAC Systems: Refrigerant pressures in air conditioning and refrigeration systems change significantly with temperature, and this relationship is used for system diagnostics and performance optimization.

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Real-World Examples

A constant-volume gas thermometer contains gas at 1.000 atm when placed in ice water (0°C). When moved to boiling water (100°C), the pressure becomes 1.366 atm. Calculate the pressure at room temperature (25°C).
  1. Convert all temperatures to Kelvin. Initial state: \(T_1 = 0 + 273.15 = 273.15\) K. Final state: \(T_2 = 25 + 273.15 = 298.15\) K.
  2. Use the initial state conditions: \(p_1 = 1.000\) atm at \(T_1 = 273.15\) K.
  3. Apply Gay-Lussac's Law: \( \frac{p_1}{T_1} = \frac{p_2}{T_2} \).
  4. Solve for the unknown pressure \(p_2\): \( p_2 = p_1 \times \frac{T_2}{T_1} \).
  5. Substitute the values: \( p_2 = 1.000 \text{ atm} \times \frac{298.15 \text{ K}}{273.15 \text{ K}} = 1.092 \text{ atm} \).
The pressure at room temperature (25°C) is 1.092 atm.
A car's cooling system operates at a gauge pressure of 15 psig at 90°C. If atmospheric pressure is 14.7 psi, what is the gauge pressure in the system when it cools down to 20°C?
  1. Convert all pressures and temperatures to absolute scales. Operating absolute pressure: \( p_1 = 15 \text{ psig} + 14.7 \text{ psi} = 29.7 \text{ psia} \).
  2. Convert temperatures to Kelvin: \( T_1 = 90 + 273.15 = 363.15 \) K. \( T_2 = 20 + 273.15 = 293.15 \) K.
  3. Use Gay-Lussac's Law to find the cold absolute pressure (\(p_2\)): \( p_2 = p_1 \times \frac{T_2}{T_1} \).
  4. Calculate \(p_2\): \( p_2 = 29.7 \text{ psia} \times \frac{293.15 \text{ K}}{363.15 \text{ K}} = 23.97 \text{ psia} \).
  5. Convert the cold absolute pressure back to gauge pressure: \( p_{2,gauge} = p_2 - p_{atm} = 23.97 \text{ psia} - 14.7 \text{ psi} = 9.27 \text{ psig} \).
The gauge pressure of the cold cooling system is 9.3 psig.
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Real-World Scenarios

Aerosol Can Warning
When an aerosol can is heated, the gas temperature rises. Since the volume is constant, the pressure increases dangerously, illustrating Gay-Lussac's Law (P₁/T₁ = P₂/T₂).
Pressure Cooker
A pressure cooker traps steam, increasing its temperature above 100°C. This directly increases the pressure inside, cooking food faster as described by Gay-Lussac's Law.
Tire Pressure
Friction heats a tire on long drives. As the air temperature inside the fixed volume of the tire rises, so does the pressure, a direct application of Gay-Lussac's Law.

Aerosol Cans: An aerosol can contains a fixed amount of propellant gas in a rigid container. If the can is left in a hot car, the temperature of the gas increases, causing a significant and dangerous rise in internal pressure, which can lead to an explosion. This is why aerosol cans have warnings not to incinerate or store them in high temperatures.

Pressure Cookers: A pressure cooker works by sealing steam inside a pot. As the water is heated past its boiling point, the temperature and pressure of the trapped steam increase dramatically. This high temperature cooks food much faster than boiling at atmospheric pressure.

Tire Pressure: The air inside a car tire has a relatively constant volume. On a long road trip, friction with the road heats the tires. This increase in temperature causes the air pressure inside the tire to rise, which is why tire pressure should be checked when the tires are cold.

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Limitations

⚠️ The law is most accurate for ideal gases. Real gases deviate from this behavior at very high pressures and low temperatures, where intermolecular forces and molecular volume become significant.
⚠️ Gay-Lussac's Law is strictly valid only for isochoric (constant volume) processes. If the container expands or contracts with temperature, the law cannot be applied directly.
⚠️ The amount of gas (number of moles) must remain constant. The law does not hold if gas is added to or leaks from the system during the process.

Common Mistakes

⚠️ Using Celsius or Fahrenheit temperatures in the ratio formula (\(p_1/T_1 = p_2/T_2\)). The direct proportionality only holds for absolute temperature (Kelvin or Rankine). Always convert temperatures to an absolute scale before calculating.
⚠️ Confusing gauge pressure and absolute pressure. Calculations must be performed using absolute pressure (\(p_{abs} = p_{gauge} + p_{atm}\)). Using gauge pressure will lead to incorrect results because it is not proportional to absolute temperature.
⚠️ Applying the law to situations where volume is not constant. If a process involves a change in volume (e.g., a piston moving in a cylinder), the Combined Gas Law or Ideal Gas Law must be used instead.
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Units and Dimensions

QuantitySymbolSI UnitDimensional Formula
Pressure\(p\)Pascal (Pa = N/m²)[M][L]⁻¹[T]⁻²
Absolute Temperature\(T\)Kelvin (K)[Θ]
Volume\(V\)cubic meter (m³)[L]³

The ratio \(p/T\) has dimensions of [M][L]⁻¹[T]⁻²[Θ]⁻¹. For Gay-Lussac's Law to be dimensionally consistent, both sides of the equation \(p_1/T_1 = p_2/T_2\) must have the same units. This is ensured by using absolute temperature and consistent pressure units (e.g., Pa, atm, or psi) on both sides.

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Study Strategy

1 🧠 Grasp the Fundamentals
  • Read the DEFINITION section to understand that for a fixed gas mass and volume, pressure is directly proportional to absolute temperature.
  • Visualize the concept: Heating a sealed container makes gas particles move faster, hitting the walls harder and more often, which increases pressure.
  • Study the molecular-level reason: Temperature is a measure of average kinetic energy. Higher temperature means faster particles, leading to more forceful collisions.
  • Focus on the key conditions: This law only applies to isochoric processes, meaning the volume and the amount of gas (moles) must remain constant.
2 📝 Commit the Formula to Memory
  • Memorize the proportionality relationship: P ∝ T. This is the core concept of the law.
  • Learn the computational form of the law: P₁/T₁ = P₂/T₂. This is the version you will use to solve problems.
  • Understand what each variable represents: P₁ and T₁ are the initial pressure and absolute temperature; P₂ and T₂ are the final values.
  • Practice rearranging the formula to solve for any of the four variables, for example, P₂ = P₁ * (T₂/T₁).
3 ✍️ Practice with Problems
  • Review the COMMON_MISTAKES section. Your top priority is to always convert temperatures to Kelvin (K = °C + 273.15) before any calculation.
  • Confirm you are using absolute pressure, not gauge pressure. Remember: P_absolute = P_gauge + P_atmospheric.
  • Solve a variety of problems. Start with simple ones finding a final pressure, then move to finding an initial temperature or pressure changes.
  • Create your own simple problem based on the Worked Example, change the numbers, and solve it to test your understanding.
4 🌍 Connect to Real-World Physics
  • Read the APPLICATIONS section and explain how a pressure cooker works using the law: Increased temperature leads to increased pressure, raising the boiling point of water.
  • Consider a real-world warning on an aerosol can: 'Do not incinerate.' The law explains that heating the fixed volume can will dangerously increase internal pressure.
  • Think about car tires on a hot day. The law explains why tire pressure increases as the temperature of the air inside rises during a long drive.
  • Explore Gas Thermometry from the APPLICATIONS section to appreciate how this principle is used to create highly accurate thermometers.
Master Gay-Lussac's Law by understanding the direct P-T relationship, rigorously converting units, and applying it to everyday phenomena from pressure cookers to car tires.

Frequently Asked Questions

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