Physics Formulae Thermal Physics Fusion(Freezing or Solidification

Subset – Definition and Properties

Discover the heat of fusion formula to calculate the energy required for a substance to melt or freeze. Learn how mass a...
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Fusion (Freezing or Solidification)

Heat of fusion (also called latent heat of fusion) is the amount of energy required to change a unit mass of a substance from solid to liquid (melting) or from liquid to solid (freezing) at its melting point temperature. During this phase change, temperature remains constant even though energy is being added or removed. The energy goes into breaking or forming the intermolecular bonds that hold the solid structure together. Different materials have vastly different heats of fusion, reflecting the strength of their molecular bonds and crystal structures.

The concept was first developed by Scottish chemist Joseph Black around 1762, who distinguished between 'sensible heat' (which changes temperature) and 'latent heat' (which causes a phase change at constant temperature). This discovery was a cornerstone in the development of thermodynamics.

Physical Properties

Heat of fusion, also known as latent heat of fusion, is the thermal energy required to change the state of a substance between solid and liquid at a constant temperature. This energy is absorbed during melting and released during freezing, without changing the substance's temperature.

PropertyDetails
NatureHeat of fusion is a scalar quantity, as it describes an amount of energy per unit mass and has no associated direction.
SI UnitsThe standard SI unit for heat of fusion is Joules per kilogram (J/kg). Other common units include kilojoules per kilogram (kJ/kg) or calories per gram (cal/g).
MagnitudeThe magnitude is a positive, intrinsic property specific to each substance. For example, the latent heat of fusion for water is approximately 334,000 J/kg.
Governing PrincipleThe concept is governed by the law of conservation of energy. The energy absorbed by a melting solid is equal to the energy released when the same mass of liquid freezes.
Dimensional FormulaThe dimensional formula is [M⁰L²T⁻²], representing energy ([ML²T⁻²]) per mass ([M]).
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Diagram & Visualization

Liquid Solid Heat Removed (-Q) Constant Temperature (Tm) Q = m Lf
Diagram showing solidification (freezing), where removing latent heat of fusion (Q) changes disordered liquid molecules to an ordered solid at constant temperature.
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Key Formulas

\[ Q = Lm \]
Heat of Fusion
\[ Q = +Lm \quad \text{(energy absorbed)} \]
Melting (Solid → Liquid)
\[ Q = -Lm \quad \text{(energy released)} \]
Freezing (Liquid → Solid)
\[ E_{total} = E_{kinetic} + E_{potential} \]
Total Internal Energy
\[ \Delta E_{potential} = Lm \]
Change in Potential Energy during Fusion
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Variables

SymbolQuantitySI UnitDescription
QHeat EnergyJoule (J)The amount of heat absorbed or released during the phase change.
LSpecific Latent Heat of FusionJoule per kilogram (J/kg)An intrinsic property of a substance; the energy required to melt one unit of mass.
mMasskilogram (kg)The mass of the substance undergoing the phase change.
T_meltingMelting Point TemperatureKelvin (K) or Celsius (°C)The specific temperature at which the phase change occurs; it remains constant throughout the process.
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Derivation and Conceptual Explanation

The formula for latent heat is empirical, derived from calorimetry experiments rather than a first-principles mathematical proof. However, it can be explained conceptually through thermodynamics. The total internal energy (E) of a system is the sum of its kinetic and potential energies.

\[ E_{total} = E_{kinetic} + E_{potential} \]

Temperature is a measure of the average kinetic energy of the molecules. During a phase change, the added energy (Q) does not increase the speed of the molecules but instead works to break the intermolecular bonds holding the solid crystal lattice together. This increases the potential energy of the system while the kinetic energy remains constant.

\[ \Delta E_{kinetic} = 0 \quad \text{(constant temperature)} \]

Therefore, all the heat added goes into changing the potential energy. The total change in potential energy is proportional to the mass (m) of the substance, with the constant of proportionality being the specific latent heat of fusion (L).

\[ Q = \Delta E_{potential} = Lm \]
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Types & Special Cases

The application of the heat of fusion concept is distinguished by the direction of the phase change and the conditions under which it occurs. The fundamental formula remains the same, but the interpretation of energy flow changes.

Type / CaseDescriptionWhen to Use
Melting (Fusion)The process of changing a substance from a solid to a liquid state. Energy, equal to the heat of fusion, is absorbed by the substance from its surroundings.Use when calculating the energy required to melt a solid at its melting point. The heat transfer (Q) is considered positive, representing energy input.
Freezing (Solidification)The process of changing a substance from a liquid to a solid state. Energy, equal to the heat of fusion, is released by the substance into its surroundings.Use when calculating the energy released as a liquid freezes at its freezing point. The heat transfer (Q) is considered negative, representing energy output.
Pressure-Dependent FusionThe value of the latent heat of fusion and the melting point temperature can vary with changes in ambient pressure. For most substances, increased pressure raises the melting point.This case is important in high-pressure environments, such as in geological processes or specialized industrial applications. For most introductory physics problems, pressure is assumed to be constant.
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Worked Example (Numerical)

Given a 1.5 kg sample of a substance with a specific latent heat of fusion of 400 kJ/kg, calculate the heat energy required to melt it completely at its melting point.
  1. Identify the given variables: mass m = 1.5 kg, and specific latent heat of fusion L = 400 kJ/kg.
  2. Choose the correct formula, which is Q = Lm.
  3. Substitute the values into the formula: Q = (400 kJ/kg) × (1.5 kg).
  4. Calculate the result: Q = 600 kJ.
The heat energy required to melt the substance is 600 kJ.
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Try It

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Applications

The concept of heat of fusion is critical in many fields:

  • Climate Science: Modeling the melting of ice sheets and glaciers, which absorbs vast amounts of solar energy and influences global weather patterns.
  • Metallurgy: Calculating the energy needed for casting, welding, and creating alloys by melting and solidifying metals.
  • Food Industry: Processes like freezing food for preservation, freeze-drying, and making ice cream rely on controlling the removal of latent heat.
  • Energy Storage: Phase Change Materials (PCMs) are used in thermal batteries and building materials to store and release thermal energy by melting and freezing.
  • Medical Applications: Cryotherapy uses the freezing process to destroy tissue, while cryopreservation uses it to store biological samples at low temperatures.
  • Electronics Cooling: PCMs are used as heat sinks to absorb large amounts of heat from electronic components during peak operation, preventing overheating.
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Real-World Examples

Calculate the total energy required to melt 2.5 kg of ice initially at 0°C and then heat the resulting water to 20°C. The latent heat of fusion for ice is 334 kJ/kg and the specific heat capacity of water is 4.2 kJ/kg·K.
  1. Calculate the energy for the phase change (melting): Q_fusion = Lm = (334 kJ/kg) × (2.5 kg) = 835 kJ.
  2. Calculate the energy to heat the liquid water from 0°C to 20°C: Q_heating = mcΔT = (2.5 kg) × (4.2 kJ/kg·K) × (20 K) = 210 kJ.
  3. Calculate the total energy by summing the two parts: Q_total = Q_fusion + Q_heating = 835 kJ + 210 kJ = 1045 kJ.
  4. Analyze the energy distribution: The melting process accounts for 835/1045 ≈ 79.9% of the total energy.
The total energy required is 1045 kJ, with the melting process consuming 835 kJ of that total.
A foundry melts 50 kg of aluminum, starting from 20°C. How much total energy is needed? (T_melting,Al = 660°C, L_Al = 321 kJ/kg, c_Al = 0.88 kJ/kg·K).
  1. Calculate the energy to heat the solid aluminum to its melting point: Q_heating = mcΔT = (50 kg) × (0.88 kJ/kg·K) × (660°C - 20°C) = 28,160 kJ.
  2. Calculate the energy required to melt the aluminum at 660°C: Q_fusion = Lm = (321 kJ/kg) × (50 kg) = 16,050 kJ.
  3. Sum the energies to find the total: Q_total = Q_heating + Q_fusion = 28,160 kJ + 16,050 kJ = 44,210 kJ.
The total energy required to heat and melt 50 kg of aluminum is 44,210 kJ or 44.21 MJ.
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Real-World Scenarios

Ice Cooling a Drink
Ice absorbs a large amount of heat (latent heat of fusion) from a drink to melt. This phase change efficiently cools the liquid.
Road Salt on Ice
Salt lowers water's freezing point, causing ice to melt by absorbing the latent heat of fusion from its surroundings.
Protecting Fruit from Frost
As water sprayed on fruit freezes, it releases its latent heat of fusion. This energy keeps the fruit's surface near 0°C, protecting it from frost damage.

Ice Cooling a DrinkWhen you add ice to a warm drink, the ice absorbs a large amount of heat energy from the liquid to undergo the phase change from solid to liquid. Because of water's high latent heat of fusion, a small amount of ice can absorb significant heat, effectively cooling the drink without a large temperature change in the ice-water mixture until all the ice is melted.

Road Salt in WinterSpreading salt on icy roads lowers the freezing point of water. This causes the ice to melt even at temperatures below 0°C because the ambient temperature is now above the new, lower melting point. The melting process still requires absorbing the latent heat of fusion from the surroundings.

Fruit Farmers and FrostOn a night when a frost is expected, fruit farmers may spray their crops with water. As the water freezes on the fruit, it releases its latent heat of fusion (Q = -Lm). This released energy helps keep the surface of the fruit at or near 0°C, preventing the plant cells inside from freezing and being damaged by colder air temperatures.

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Limitations and Assumptions

⚠️ The formula Q = Lm assumes the process occurs at constant pressure. Significant pressure changes can alter the melting point and the latent heat of fusion.
⚠️ This formula is most accurate for pure substances. Impurities (like salt in water) can change the melting point and cause the substance to melt over a range of temperatures rather than at a single, fixed point.
💡 The formula applies only during the phase transition itself. It does not account for the energy needed to bring the substance to its melting point (sensible heat, Q=mcΔT) or to heat it further after it has melted.

Common Mistakes

⚠️ Forgetting the phase change energy. In multi-step problems (e.g., heating ice, melting it, then heating the water), students often forget to include the Q = Lm step. This latent heat is usually a very large component of the total energy.
⚠️ Unit conversion errors. The latent heat of fusion (L) is often given in kilojoules per kilogram (kJ/kg), while mass (m) might be given in grams. Always convert mass to kg before calculating to ensure units are consistent.
⚠️ Ignoring the sign convention. Melting requires energy input, so Q should be positive. Freezing releases energy, so Q should be negative. Forgetting this can lead to errors in energy balance calculations.
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Units and Dimensions

QuantitySymbolSI UnitDimensions
Heat EnergyQJoule (J)[M][L]²[T]⁻²
Massmkilogram (kg)[M]
Specific Latent Heat of FusionLJoule per kilogram (J/kg)[L]²[T]⁻²

Dimensional analysis confirms the formula's consistency: The dimensions of L multiplied by the dimensions of m are \( [L]^2[T]^{-2} \times [M] = [M][L]^2[T]^{-2} \), which are the dimensions of energy (Q).

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Study Strategy

1 🧠 Grasp the Fundamentals
  • Read the DEFINITION section to understand that latent heat of fusion is the energy for a phase change at a constant temperature.
  • Visualize how this energy is used to break intermolecular bonds during melting or form them during freezing, not to change the temperature.
  • Distinguish clearly between melting (energy absorbed, positive Q) and freezing/solidification (energy released, negative Q).
  • Contrast the heat of fusion (solid-liquid transition) with the heat required to change the temperature of a solid or liquid (Q=mcΔT).
2 📝 Commit the Formula to Memory
  • Write the formula Q = mL ten times. Verbally state, 'Heat equals mass times specific latent heat of fusion.'
  • Create a flashcard for each variable: Q (heat energy in Joules), m (mass in kilograms), and L (specific latent heat of fusion in J/kg).
  • Recognize that this formula applies *only* during the phase change itself, where temperature is constant.
  • Practice rearranging the formula to solve for mass (m = Q/L) or latent heat (L = Q/m) to build algebraic fluency.
3 ✍️ Practice with Problems
  • Solve a basic problem: Calculate the heat needed to melt 500g of ice at 0°C. Be careful with units.
  • Review the COMMON_MISTAKES section. Now, solve a multi-step problem, like heating ice, melting it, and then heating the water, ensuring you include the Q=mL step.
  • Pay special attention to unit conversions noted in COMMON_MISTAKES. Convert all masses to kg and energy to Joules before calculating.
  • Attempt a conceptual problem: Explain why a large body of water, like a lake, freezes slowly and moderates the local climate.
4 🌍 Connect to Real-World Physics
  • Read the APPLICATIONS section and explain how metallurgy depends on calculating the energy needed to melt and solidify metals for casting.
  • Consider the Climate Science application. Discuss how the immense energy absorbed by melting glaciers can impact global weather patterns.
  • Relate the concept to the Food Industry application. Why does freezing effectively preserve food? Think about the energy removed.
  • Observe ice in a drink. Note how it holds the temperature at a steady 0°C (32°F) until the last bit is melted, a direct view of latent heat in action.
Master the energy of phase changes by understanding the concept, memorizing the formula, practicing with care, and observing its power in the world.

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